1st box contains mixture in the ratio 5:3.

Type 1 in 1st mixture = 6X x 5/8 = 15X/4 kg.

And type 2 in 1st mixture = 6X – 15X/4 = 9X/4 kg

Type 1 in 2nd mixture = 4X x 4/7 = 16X/7 kg.

And type 2 in 2nd mixture = 4x – 16X/7 = 12X/7 kg

Type 1 in 3rd mixture = 3X x 3/4 = 9X/4 kg.

And type 2 in 3rd mixture = 3X – 9X/4 = 3X/4 kg

Totally, type 2 in final mixture = 9X/4 + 12X/7 + 3X/4 = 132X/28 = 33X/7

Required ratio = 58X/7 : 33X/7 = 58:33

AK Rehman can row 180 km upstream and 120 km downstream in 28 hours.

Distance while travelling upstream / Effective upstream speed + Distance while travelling downstream / Effective downstream speed = Total time taken for upstream and downstream

Or 180/x + 120/y = 28 …(1)

Similar to eq 1 we can form a new equation as below

90/x + 90/y = 16 ….(2)

Multiply by 2 on both sides of eq 2 we get,

180/x + 180/y = 32….. (3)

(1) – (3) = 180/x + 120/ y – 180/x – 180/y = 28 – 32 = -4

-60/y = -4

Effective downstream speed = y = 15

Effective upstream speed = x = 9

Speed of Boat = Effective upstream speed + Effective downstream speed / 2 = (15 +9)/2 = 12.

Speed of current can be calculated using the below formula :

Speed of Current = Effective upstream speed – Effective downstream speed / 2 = (15 – 9)/2 = 3.

Let their altitudes be h1 and h2.

Ratio of their area’s = [1/2 x p x h1] / [1/2 x q x h2]…(1)

From (1) & (2), we have,

[1/2 x p x h1] / [1/2 x q x h2] = r/s

q x r x h2 = p x s x h1

h1/h2 = qr/ps

Hence, required ratio is qr:ps.

This is an A.P. in which a = 11 and d = 6.

Then the sum of n terms = 11 + 17 + 23 +…+ tn = 256.

We have to find the n.

Here, Sn = 256 = (n / 2) [2×11 + (n-1)6].

(n / 2) [22 + (n-1) 6] = 256

22n + 6n

6n

3n

Here, a = 3, b = 8, c = -256 and x = n.

n = [-8 (+/-)sqrt (8

= [-8 (+/-)sqrt (64 + 3072) ] / 2×3.

= [-8 (+/-) sqrt(3136) ] / 6.

= [-8 (+/-)56] / 6

= [-4 (+/-)28] / 3

i.e., n = (-4 + 28)/3 or (-4 – 28)/3

n is either 8 or -32/3

Since n is a non-negative whole number, n value will be 8.

So the number of terms of the series to sum 256 is 8

Given difference of highest and lowest is 86.

Then, his lowest score = X – 86

And, the aggregate of highest and lowest = X + X – 86 = 2X – 86.

Then, his total score = 50 x 20.

Total of 18 tests = 46 x 18 …(2)

We have, 50 x 20 – (2X – 86) = 46 x 18

1000 + 86 – 2X = 828

2X = 258

X = 129.

Hence, the highest score is 129.

By observing, we can conclude that questions are in the general form AB + CD = (AB – CD)/8

That is,

128 + 8 = 128 – 8 /8 = 120 /8 = 15

82 + 10 = 82-10 /8 = 72/8 = 9

316 + 12 = 316-12 / 8 = 304/8 = 38

624 + 8 = 624–8 /8 = 616/8 = 77.

Hence, the answer is 77.

C + Y = (308 – 249) = 59 …. (2)

Therefore, speed in downstream = (X+6) km/hr (by using formula 2)

And, speed in upstream = (X-6) km/hr

2X+12 = 3X-18

X = 30km/hr.

Marked price is 20% more than it’s cost price = Rs.120

Then its selling price = (CP + Profit) = Rs.112

Rs.120 – Rs.112 = Rs.8

Required discount % = 8/120 x 100 = 20/3 %

Hence the answer is 20/3%.

Total number of kids in the school(when everyone is present) = 350.

If everyone is present, number of chocolates per kid = X/350 chocolates …(1)

Therefore, total number of kids present = 350 – 140 = 210

Therefore, number of chocolates per present kid = X/210 chocolates …(2)

The powers of 2 and 11 are divisible by 3.

Therefore, 10648 is a perfect cube.

The powers of 3 and 5 are divisible by 3.

Therefore, 91125 is a perfect cube.

The powers of 2, 3 and 7 are divisible by 3.

And so, 74088 is a perfect cube.

The power of 3 is divisible by 3.

So, 19683 is a perfect cube.

Hence, the answer is option D.

Since the trains are moving in the same direction,the time required to cross each other = (a + b)/(u – v) sec

a + b = 300 + 400 = 700 m.

And, u – v = (90 – 80)km/hr = 10 km/hr.

10 km/hr = 10 x 5/18 m/sec = 50/18 m/s.

Now, the required time = 700 x 18/50 sec = 252 sec.

This can be written as, 5/100 x 68.25 + 45/100 x 95/100 x 1755 = 35/100 x ? /100 x 6350.

5/100 x 6825/100 + 45/100 x 95/100 x 1755 = 35/100 x ? /100 x 6350.

5x 6825/10000 + 45x 95/10000 x 1755 = 35 x ? /10000 x 6350

5 x 6825+ 45 x 95 x 1755 = 35 x ? x 6350

5 x 273 + 9 x 19 x 1755 = 35 x ? x 254

273 + 9 x 19 x 351 = 7 x ? x 254

60924 = 1778 x ?

? = 60924/1778 = 33.91

Hence the answer is 33.91.

Then 3h and r/3 are the height and radius of new cone respectively.

We know that, the volume of a right circular cone of height h and radius r is 1/3 (pi)(r

Volume of new cone = 1/3 (pi) (r / 3)

= 1/3 (1/3 (pi) (r

3rd number: 2nd x 3 – 2 = 28 x 3 – 2 = 84 – 2 = 82

4th number: 3rd x 2 – 2 = 82 x 2 – 2 = 164 – 2 = 162

5th number: 4th x 3 – 2 = 162 x 3 – 2 = 486 – 2 = 484

6th number: 5th x 2 – 2 = 484 x 2 – 2 = 968 – 2 = 966 (note that, there is 1006 instead of 966).

Given average = a + b + c + d / 4 = 22.5 …(1)

B’s age is 1/4 of C, then b = c/4

C’s age is 7 times D, then c = 7d

Sub. c value in b, we have b = 7d/4.

Sub. b value in a, we have a = 21d/4.

(21d/4) + (7d/4) + 7d + d = 22.5 x 4

(21d + 7d + 32d) = 22.5 x 16

60d = 22.5 x 16

d = 22.5 x 16 / 60 = 6.

c = 7d = 42,

b = 7d/4 = 10.5

and a = 3b = 31.5.

Therefore, the eldest age is 42.

{

int x=11,y=6,z;

z=x==5 || !=4;

printf(“z=%d”,z);

}

{

int i=5;

if(i>5);

{

i=100;

printf(” %d “,i);

}

}